forked from External/mage
188 lines
No EOL
5.2 KiB
Java
188 lines
No EOL
5.2 KiB
Java
/*
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NaturalOrderComparator.java -- Perform 'natural order' comparisons of strings in Java.
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Copyright (C) 2003 by Pierre-Luc Paour <natorder@paour.com>
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Based on the C version by Martin Pool, of which this is more or less a straight conversion.
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Copyright (C) 2000 by Martin Pool <mbp@humbug.org.au>
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This software is provided 'as-is', without any express or implied
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warranty. In no event will the authors be held liable for any damages
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arising from the use of this software.
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Permission is granted to anyone to use this software for any purpose,
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including commercial applications, and to alter it and redistribute it
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freely, subject to the following restrictions:
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1. The origin of this software must not be misrepresented; you must not
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claim that you wrote the original software. If you use this software
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in a product, an acknowledgment in the product documentation would be
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appreciated but is not required.
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2. Altered source versions must be plainly marked as such, and must not be
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misrepresented as being the original software.
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3. This notice may not be removed or altered from any source distribution.
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*/
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package mage.client.util;
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import java.util.*;
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public class NaturalOrderComparator implements Comparator
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{
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int compareRight(String a, String b)
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{
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int bias = 0;
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int ia = 0;
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int ib = 0;
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// The longest run of digits wins. That aside, the greatest
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// value wins, but we can't know that it will until we've scanned
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// both numbers to know that they have the same magnitude, so we
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// remember it in BIAS.
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for (;; ia++, ib++)
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{
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char ca = charAt(a, ia);
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char cb = charAt(b, ib);
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if (!Character.isDigit(ca) && !Character.isDigit(cb))
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{
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return bias;
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}
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else if (!Character.isDigit(ca))
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{
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return -1;
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}
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else if (!Character.isDigit(cb))
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{
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return +1;
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}
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else if (ca < cb)
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{
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if (bias == 0)
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{
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bias = -1;
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}
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}
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else if (ca > cb)
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{
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if (bias == 0)
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bias = +1;
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}
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else if (ca == 0 && cb == 0)
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{
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return bias;
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}
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}
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}
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@Override
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public int compare(Object o1, Object o2)
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{
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String a = o1.toString();
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String b = o2.toString();
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int ia = 0, ib = 0;
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int nza = 0, nzb = 0;
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char ca, cb;
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int result;
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while (true)
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{
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// only count the number of zeroes leading the last number compared
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nza = nzb = 0;
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ca = charAt(a, ia);
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cb = charAt(b, ib);
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// skip over leading spaces or zeros
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while (Character.isSpaceChar(ca) || ca == '0')
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{
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if (ca == '0')
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{
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nza++;
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}
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else
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{
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// only count consecutive zeroes
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nza = 0;
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}
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ca = charAt(a, ++ia);
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}
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while (Character.isSpaceChar(cb) || cb == '0')
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{
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if (cb == '0')
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{
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nzb++;
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}
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else
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{
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// only count consecutive zeroes
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nzb = 0;
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}
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cb = charAt(b, ++ib);
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}
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// process run of digits
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if (Character.isDigit(ca) && Character.isDigit(cb))
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{
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if ((result = compareRight(a.substring(ia), b.substring(ib))) != 0)
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{
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return result;
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}
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}
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if (ca == 0 && cb == 0)
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{
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// The strings compare the same. Perhaps the caller
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// will want to call strcmp to break the tie.
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return nza - nzb;
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}
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if (ca < cb)
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{
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return -1;
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}
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else if (ca > cb)
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{
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return +1;
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}
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++ia;
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++ib;
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}
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}
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static char charAt(String s, int i)
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{
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if (i >= s.length())
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{
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return 0;
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}
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else
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{
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return s.charAt(i);
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}
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}
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public static void main(String[] args)
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{
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String[] strings = new String[] { "1-2", "1-02", "1-20", "10-20", "fred", "jane", "pic01",
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"pic2", "pic02", "pic02a", "pic3", "pic4", "pic 4 else", "pic 5", "pic05", "pic 5",
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"pic 5 something", "pic 6", "pic 7", "pic100", "pic100a", "pic120", "pic121",
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"pic02000", "tom", "x2-g8", "x2-y7", "x2-y08", "x8-y8" };
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List orig = Arrays.asList(strings);
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System.out.println("Original: " + orig);
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List scrambled = Arrays.asList(strings);
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Collections.shuffle(scrambled);
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System.out.println("Scrambled: " + scrambled);
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Collections.sort(scrambled, new NaturalOrderComparator());
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System.out.println("Sorted: " + scrambled);
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}
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} |